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We are given two arrays
AandBof words. Each word is a string of lowercase letters.Now, say that word
bis a subset of wordaif every letter inboccurs ina, including multiplicity. For example,"wrr"is a subset of"warrior", but is not a subset of"world".Now say a word
afromAis universal if for everybinB,bis a subset ofa.Return a list of all universal words in
A. You can return the words in any order.
Example 1:
Input: A = ["amazon","apple","facebook","google","leetcode"], B = ["e","o"]Output: ["facebook","google","leetcode"]Example 2:
Input: A = ["amazon","apple","facebook","google","leetcode"], B = ["l","e"]Output: ["apple","google","leetcode"]Example 3:
Input: A = ["amazon","apple","facebook","google","leetcode"], B = ["e","oo"]Output: ["facebook","google"]Example 4:
Input: A = ["amazon","apple","facebook","google","leetcode"], B = ["lo","eo"]Output: ["google","leetcode"]Example 5:
Input: A = ["amazon","apple","facebook","google","leetcode"], B = ["ec","oc","ceo"]Output: ["facebook","leetcode"]
Note:
1 <= A.length, B.length <= 100001 <= A[i].length, B[i].length <= 10A[i]andB[i]consist only of lowercase letters.- All words in
A[i]are unique: there isn'ti != jwithA[i] == A[j].
Approach #1: String. [Java]
class Solution { public List wordSubsets(String[] A, String[] B) { int[] init = new int[26], temp; for (String b : B) { temp = counter(b); for (int i = 0; i < 26; ++i) { init[i] = Math.max(init[i], temp[i]); } } List ret = new ArrayList<>(); for (String a : A) { temp = counter(a); int i = 0; for (i = 0; i < 26; ++i) { if (temp[i] < init[i]) break; } if (i == 26) ret.add(a); } return ret; } public int[] counter(String b) { int[] temp = new int[26]; for (int i = 0; i < b.length(); ++i) { temp[b.charAt(i)-'a']++; } return temp; }}
Reference:
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